A person has a coin, one standard deck of 52 playing cards and a six-sided number cube. How many different outcomes are possible for picking a card, flipping the coin, and rolling the number cube? a-624 b-60 c-4 1/3 d-1/624

Hence there are 624 different possible outcomes.

Step-by-step explanation:

Given:

There is one coin, a deck and a dice

To Find:

Number of possibility for pick card, flipping coin and rolling dice.

Solution:

There are three different types of events outcomes as

1) Flipping a coin:

It will result in head or tail.

There are 2 possibilities.

2)Picking a card there are 52 cards:

So  it will result in any card and no of possibilities will be 52

3)Rolling a dice:

There are 6 numbers so no.of possibilities 6.

Hence to get all possible outcomes it is as follows:

The operator used is "AND" Hence we have to multiple each possibilities.

(i.e. Flipping coin AND Rolling Dice AND Picking card).

Possible Outcomes=6*52*2

=624.

Hence there are 624 different possible outcomes.

Step-by-step explanation:

Given:

There is one coin, a deck and a dice

To Find:

Number of possibility for pick card, flipping coin and rolling dice.

Solution:

There are three different types of events outcomes as

1) Flipping a coin:

It will result in head or tail.

There are 2 possibilities.

2)Picking a card there are 52 cards:

So  it will result in any card and no of possibilities will be 52

3)Rolling a dice:

There are 6 numbers so no.of possibilities 6.

Hence to get all possible outcomes it is as follows:

The operator used is "AND" Hence we have to multiple each possibilities.

(i.e. Flipping coin AND Rolling Dice AND Picking card).

Possible Outcomes=6*52*2

=624.

Step-by-step explanation:

goog may have it for you

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: