A triangular pyramid has a base with an area of 7 square centimeters and lateral faces with bases of 4 centimeters. What is the surface area of the pyramid?

79cm

Step-by-step explanation:

I took the liberty of getting the complete question suce the one provided isn't and here it goes:

a trianglular pyramid has a base with an area of 7 square centimeters

and layeral faces with bases of 4 centimeters and height of 12

centimeters. what is the surface area of the pyramid

--- All we need to do here is to add up the areas of the base and the lateral faces.

Since we are dealing with a triangular pyramid there are 3 lateral faces.

The area of the base is given as 7 square cm

Each face is a triangle with base = 4 cm and height = 12 cm so

each face has an area of

A = (1/2) × base × height = (1/2) × 4 × 12 = 24 square cm

There are 3 lateral faces so the total surface area is

3x + 7 = 3 × 24 + 7 = 79 cm²

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply