The drama club is selling tickets to their play to raise money for the show's expenses.

Each student ticket sells for $8 and each adult ticket sells for $13. The auditorium can

hold at most 70 people. The drama club must make at least $730 from ticket sales to

cover the show's costs. If 41 adult tickets were sold, determine the minimum number

of student tickets that the drama club must sell in order to meet the show's expenses.

If there are no possible solutions, submit an empty answer.

25

Step-by-step explanation:

Ticket sale (student) = $8

Ticket sale (adult) = $13

The hall can contain 70 people.

Number of adult tickets sold = 41

Cost of show = $730

Let the number of student ticket sold = x

Setting an algebraic equation to show represent the cost of the show and set minimum target of ticket to be sold.

730 = (41 * 13) + (x * 8)

730 = 533 + 8x

8x = 730 - 533

8x = 197

X = 197 / 8

x = 24.6 = 25

The minimum number of student tickets to be sold is 25

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c