At a point 400 feet from the base of a building, the angle of elevation to the top of the building is 60◦. Find the height of the building (leave your answer in radical form)

The height of the building is 400√3

Step-by-step explanation:

Given:

Angle of elevation to the top of the building = 60°

Distance from the observer to the base of it = 400 ft

We have to find the height of the building.

Let the height of the building be "h" ft

Using trigonometric ratio:

⇒

So,

Considering adjacent side as 400 ft.

⇒

⇒

⇒

⇒                         ...tan(60) = √3

⇒ ft

The height of the building is 400 Sq-rt (3) ft in terms of radical form and in decimals it is 692.8 ft.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )