The area of a circular base of the larger cylinder is 81π. The area of a circular base of the smaller cylinder is 9π.

Make a conjecture about the similar solids. How is the scale factor and the ratio of the surface areas related? Check all that apply.

- The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.
- The surface area of the larger cylinder is 32, or 9, times the surface area of the smaller cylinder.
- If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

A & C

The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.

If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

Step-by-step explanation:

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

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- nicole

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v