[ Let f ( x ) ] = [ 3 x 2 + 2 x ] , [ g ( x ) ] = [ 3 x + 9 ] , [ h ( x ) ] = [ 12 + x ] , [ What is f ( g ( 3 ) ) ? ] [ Let f ( x ) ] = [ 3 x 2 + 2 x ] , [ g ( x ) ] = [ 3 x + 9 ] , [ h ( x ) ] = [ 12 + x ] , [ What is f ( g ( 3 ) ) ? ]

The value of f(g(3) =  1,008

Step-by-step explanation:

Step:-1

Given f(x) =

and g(x) = 3x+9

      h(x) = 12+x

Given g(x) = 3x+9

  put x =3

      g(3) = 3(3)+9

       g(3) = 18

Step :-(2)

f(g(3)) = f(18)

f(g(3) = 3(18)^2 +2(18) (since f(x) =)

        = 1,008

Final answer:-

The value of f(g(3) =  1,008

answer: it is 1: 47 pm

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680