Mathematics, 15.04.2020 19:55, 182075
In a recent text message survey, 4,000 randomly selected teenagers were asked to cite their favorite Florida college football team. Twenty-two of 40 teenagers said the Florida Gators are their favorite team. A 99% confidence interval to estimate the true proportion of teenagers who like the Florida Gators is found to be (0.3474, 0.7526). Which of the following is a correct interpretation of the confidence level? (4 points)
Ninety-nine percent of all samples of this size would yield a confidence interval of (0.3474, 0.7526).
There is a 99% chance that the true proportion of teenagers who like the Florida Gators is (0.3474, 0.7526).
Ninety-nine percent of all the samples of size 4,000 lie in the confidence interval (0.3474, 0.7526).
Ninety-nine percent of the time, the procedure used to generate this interval will capture the true proportion of teenagers who like the Florida Gators.
There is a 99% chance that randomly selected teenagers will be part of the 55% who like the Florida Gators.
Answers: 2
Mathematics, 21.06.2019 13:40, aronrobinson4
1234567891011 match the reasons with the statements in the proof. given: j | | k m 1 = m 3 prove: l | | m 1. j||k, mâ 3 = mâ 1 if lines are ||, then corresponding angles are =. 2. mâ 1 = mâ 2 if alternate interior angles are =, then lines are ||. 3. mâ 2 = mâ 3 substitution 4. l||m given
Answers: 3
Mathematics, 21.06.2019 15:30, megancrader11
Will mark brainliest if you answer ! the taco shop sold 198 lunches friday. this number is 3 more than 3 times the number they sold monday. let n represent the number of lunches sold monday. which equation shows an equality between two different ways of expressing the number of lunches sold on friday? a. n â 3 = 198 b. 3n â 3 = 198 c. 3n + 3 = 198 d. n + 3 = 198
Answers: 1
In a recent text message survey, 4,000 randomly selected teenagers were asked to cite their favorite...
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