If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept?

A) The x-intercept decreases.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Consider the function f(x) = mx + b, where m > 0.

If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept?

A) The x-intercept decreases.

B) The x-intercept increases.

C) The x-intercept approaches zero.

D) The x-intercept remains the same

Here is my

Given the function f(x) = mx + b, where m > 0.

x-intercept happen when y =0

When b decreases and m stay the same, the value of f(x) will be decreased. For example:  f(x)= 2x + 3 = 0

When  b unchanged, m unchanged we have: 2x + 3 = 0 <=> x = -3/2

When  b decreases to 2, m unchanged we have: 2x + 2 = 0 <=> x = -1

Obviously that,  -1 < -3/2 so the x-intercept will be decreased

the answer is d. 75%

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!