A bank manager estimates that an average of two customers enter the tellers’ queue every five minutes. Assume that the number of customers that enter the tellers’ queue is Poisson distributed. What is the probability that exactly three customers enter the queue in a randomly selected five-minute period?

a. 0.2707
b. 0.0902
c. 0.1804
d. 0.2240

Option C) 0.1804  

Step-by-step explanation:

We are given the following information in the question:

Mean customers enter the tellers’ queue every five minutes = 2

Thus, the number of customers that enter the tellers’ queue is Poisson distributed

Formula:

We have to evaluate:

0.1804 is the probability  that exactly three customers enter the queue in a randomly selected five-minute period.

Thus, the correct answer is

Option C) 0.1804

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

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