Factoring a quadratic in the equation z^2-7z+10=0 what are the a b and c values (pick it blurry but I wrote what it say need answer asap

a=1 b = -7 and c = 10

Step-by-step explanation:

z^2-7z+10=0

The quadratic is written in the form

ax^2 +bx+c=0

Letting x become z

az^2 + bz+c =0

a=1 b = -7 and c = 10

a = 1, b = -7, c = 10

Step-by-step explanation:

Az² + Bz + C is the general form of a quadratic

Where,

A is the coefficient of z²

B is the coefficient of z

C is the constant

z² -7z + 10=0

a = 1, b = -7, c = 10

In case you need the factorized form too:

z² - 7z + 10 = 0

z² - 5z - 2z + 10 = 0

z(z - 5) -2(z - 5) = 0

(z - 2)(z - 5) = 0

29.5977692753

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.