A rectangular page is to contain 24 square inches of printed material. The margins at the top and at the bottom are each 1.5 inches. The margins at the left and at the right are each 1 inch. What dimensions should the page have so that the least amount of material is used?

Height: 9 in

Length: 6 in

Width: 4 in

Step-by-step explanation:

Given that A rectangular page is to contain 24 square inches

Let y is the length of the rectangle Let x is the width of the  rectangle  

We know that:

The area of the the rectangle: A = length* width =24

<=> x*y = 24

<=> y = 24/x

As given in the question:

Height (h)     h  =  y  + 2*1.5  <=>     h =  y  + 3   Lenght  (l)        =  x + 2

<=> The area = h*l

= (y  + 3  ) (x + 2 )

=  (24/x+3) (x+2)

= 30  +  48 /x  +  3x

Taking derivatives on both sides of the equation

A´(x)  =  -48/x²  + 3

Let A´(x) = 0, we have:

-48/x²  + 3  = 0

<=> x = 4 in

When x=4 in we have y = 24/4 = 6  and h = 6+3 = 9

=> A (min) = 6*9 = 54

So the dimensions are:

Height: 9 in

Length: 6 in

Width: 4 in

10feet apart then both

Ithink you're supposed to multiply 12.50 which is how much he makes per hour and then multiply it by each number then add whats left togrther and there's your answer