Two separate samples receive different treatments. After treatment, the first sample has n = 6 with SS = 236, and the second has n 5=12 with SS = 340.

a. Find the pooled variance for the two samples.
b. Compute the estimated standard error for the sample mean difference.

a) 33.88 and b) 2.91.

Step-by-step explanation:

Since we have given that

Sample n₁ = 6

SS = 236

Sample n₂ = 12

SS = 340

So, we need to find the following:

a. Find the pooled variance for the two samples.

So, it becomes,

b. Compute the estimated standard error for the sample mean difference.

Hence, a) 33.88 and b) 2.91.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0