Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.3 pounds. What is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds?

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

Standard error due to sampling =

P(sample of 20 boxers is more than 167 pounds)

Calculation the value from standard normal z table, we have,  

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

greater than one

step-by-step explanation:

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a