Given three non-collinear points $A$, $B$, and $C$, construct three circles that are pairwise tangent at these points. (In other words, two of the three circles are tangent at $A$, two are tangent at $B$, and two are tangent at $C$.) Are there any cases where such circles do not exist

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

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b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

i think the correct option is the second option.