Population Standard Deviation 6.0000
Sample Size 10
Sample Mean 66.8000
Confide...
Mathematics, 15.04.2020 00:50, decoreyjpaipxv
Population Standard Deviation 6.0000
Sample Size 10
Sample Mean 66.8000
Confidence Interval
Confidence Coefficient 0.98
Lower Limit
Upper Limit
Hypothesis Test
Hypothesized Value 60
Test Statistic
P-value (Lower Tail)
P-value (Upper Tail)
P-value (Two Tail) 0.0004
Sample Size 10
Sample Mean 66.8000
Sample Standard Deviation 4.89944
Confidence Interval
Confidence Coefficient 0.98
Lower Limit
Upper Limit
Hypothesis Test
Hypothesized Value 60
Test Statistic
P-value (Lower Tail)
P-value (Upper Tail)
P-value (Two Tail) 0.0018
Studies show that massage therapy has a variety of health benefits. Ten typical one-hour massage therapy sessions were randomly selected, the amount charged for those sessions recorded, and this information put into Excel. Does the data suggest that the average charge for a typical one-hour massage therapy session is greater than $60 at α=.01? Based on this paragraph of text, use the correct excel output above to answer the following question.
For the hypothesis stated above, what is(are) the critical value(s)?
a. None of the answers is correct
b. 2.764
c. 2.33
d. 2.575
e.2.821
Answers: 3
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In a test for esp (extrasensory perception), the experimenter looks at cards that are hidden from the subject. each card contains either a star, a circle, a wave, a cross or a square.(five shapes) as the experimenter looks at each of 20 cards in turn, the subject names the shape on the card. when the esp study described above discovers a subject whose performance appears to be better than guessing, the study continues at greater length. the experimenter looks at many cards bearing one of five shapes (star, square, circle, wave, and cross) in an order determined by random numbers. the subject cannot see the experimenter as he looks at each card in turn, in order to avoid any possible nonverbal clues. the answers of a subject who does not have esp should be independent observations, each with probability 1/5 of success. we record 1000 attempts. which of the following assumptions must be met in order to solve this problem? it's reasonable to assume normality 0.8(1000), 0.2(1000)%30 approximately normal 0.8(1000), 0.2(1000)% 10 approximately normal srs it is reasonable to assume the total number of cards is over 10,000 it is reasonable to assume the total number of cards is over 1000
Answers: 1
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