Plan A offers an annual membership fee of $72 and you pay 75% of the listed price. Plan B offers an annual membership of $30 and you pay 90% of the listed price. How many dollars of merchandise do you need to purchase so that you pay the same amount under both plans?

You need to purchase $280 dollars of merchandise  to pay the same amount under both plans.

Step-by-step explanation:

Hi, to answer this question we have to write equations for each plan's cost.

The cost of plan a (A) is equal to the annual fee (72) plus y 75% (75/100= 0.75) of the listed price(x)

A =72 + 0.75 x

Same process for the cost of plan B (B)

B= 30+ 0.90 x

If both costs are equal

A=B

So:

72 + 0.75 x = 30+ 0.90 x

Solving for x:

72-30 = 0.9x-0.75x

42 = 0.15x

42/0.15 =x

x= $280

You need to purchase $280 dollars of merchandise to pay the same amount under both plans

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

21/58.

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