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The base of pyramid A is a rectangle with a length of 10 meters and a width of 20 meters. The base of pyramid B is a square with 10 meter sides. The heights of the
pyramids are the same
The volume of pyramid Ais
the volume of pyramid B. If the height of pyramid increases to twice that of pyramid A the new volume of pyramid B
the volume of pyramid A
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the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

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