Water runs into a conical tank at the rate of 9 ft 3/min. the tank is standing, inverted, and has a height of 10 feet and a base diameter of 10 feet. At what rate is the radius of the water in the tank increasing when the radius is two feet

0.36ft/min

Step-by-step explanation:

We are given that

Diameter of  tank,d=10ft

Radius,

Height of tank,h=10 ft

We have to find the rate at which radius of the water in the tank increasing when r=2 ft

Volume of conical tank=

Substitute the values

Differentiate w.r.t t

Substitute the values

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )