A bag contains 4 red marbles, 5 blue marbles, and 3
green marbles. Two marbles are picked at random. What
is the fractional probability that 2 red marbles are picked
if the first marble was not returned before the second
was chosen?

will give brainliest

1 / 11 is the probability that 2 red marbles are picked without replacement.

Step-by-step explanation:

A bag contains 4 red marbles, 5 blue marbles, and 3  green marbles.

The total number of marbles in the bag = 12 marbles.

Two marbles are picked at random.

We need to find the Probability that two marbles are picked without replacement.

P (first red) = No.of red marbles / Total marbles

⇒ 4 / 12

After the first marble taken out, the total marbles in the bag will be reduced to 11 marbles and the no.of red marbles will become 3.

P (second red) = No.of remaining red marbles / Total marbles

⇒ 3 / 11

To find the probability of 2 red marbles :

⇒ P (first red) × P (second red)

⇒ 4/12 × 3/11

⇒ 12/132

⇒ 1/11

∴ 1 / 11 is the probability that 2 red marbles are picked without replacement.

1/11

Step-by-step explanation:

1/11

the answers c

they go with it happens or they mite give a chance?

step-by-step explanation: