Car A starts in Sacramento at 11am. It travels along a 400 mile route to Los Angeles at 40 mph. Car B starts from Los Angeles at noon and travels to Sacramento along the same route at 75 mph. The route goes past Fresno which is 150 miles along the route from Los Angeles. How far from Fresno are the cars when they meet?

Distance from Fresno where both cars meet = 210 - 150 = 60 miles

Step-by-step explanation:

let x = distance travelled by A from Sacramento

y = distance travelled by B from Los Angeles

t = time after 12 noon that they meet

x = 50(t + 1)

y = 400 - x = 75(t) or x = 400 - 75t

so: 50(t + 1) = 400 - 75t

     50t + 50 = 400 - 75t

     50t + 75t = 400 - 50

                 t = 2,8 hrs

so y = 400 - 75(2.8) = 210 miles from Los Angeles  

distance from Fresno where both cars meet = 210 - 150 = 60 miles

the answer is 54 sq. ft. i just did this question, on odyssey ware, and it was right. make brainliest.

fyuh

step-by-step explanation:

gvfvhv