Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance level to test the claim that more than 20% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Upper H 0: pequals0.20 Upper H 1: pnot equals0.20 B. Upper H 0: pequals0.20 Upper H 1: pless than0.20 C. Upper H 0: pgreater than0.20 Upper H 1: pequals0.20 D. Upper H 0: pequals0.20 Upper H 1: pgreater than0.20

Null Hypothesis, : p = 0.20  

Alternate Hypothesis, : p > 0.20  

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.

Let p = population proportion of users who develop nausea

So, Null Hypothesis, : p = 0.20  

Alternate Hypothesis, : p > 0.20  

Here, null hypothesis states that 20% of users develop nausea.

And alternate hypothesis states that more than 20% of users develop nausea.

The test statistics that would be used here is One-sample z proportion test statistics.

                     T.S. =     ~ N(0,1)

where,   = proportion of users who develop nausea in a sample of 241 subjects =    

             n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

answer:

your answer is: c. 196 7/8 in^3.