Solution A is an $80\%$ acid solution. Solution B is a $30\%$ acid solution. (a) Find the amount of Solution A (in mL) that must be added to $500$ mL of Solution B in order to produce a $70\%$ acid solution. (b) Find the amount of Solution A and Solution B (in mL) that can be combined in order to form a $100$ mL solution that is $50\%$ acid. (c) Does there exist a combination of Solution A and Solution B that is $90\%$ acid

(a) (b) (c)NO

Step-by-step explanation:

GIVEN: Solution A is an acid solution. Solution B is a acid solution.

TO FIND: (a) Find the amount of Solution A (in mL) that must be added to of Solution B in order to produce a acid solution. (b) Find the amount of Solution A and Solution B (in mL) that can be combined in order to form a solution that is acid. (c) Does there exist a combination of Solution A and Solution B that is acid.

SOLUTION:

(a)

Let total amount of solution A added be

Total amount of mixture

As resulting solution is   acid solution.

Amount of acid in final solution is sum of acid in both solutions

(b)

Let amount of Solution A be

Amount of solution B

As resulting solution is acidic solution

Amount of acid in final solution is sum of acid in both solutions

Amount of solution B

(c)

No as concentration of final solution can not be greater than one with higher concentration.

is there a picture

step-by-step explanation:

it would be 4 over -2 divided by -1 over 3.

if you want a solution it would be 4

you flip it so it would be 4/-2 divided by 3/-1 then it would be 12/3 and you would simplify it to 4