Based on a poll, 6464% of Internet users are more careful about personal information when using a public Wi-Fi hotspot. What is the probability that among threethree randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot? How is the result affected by the additional information that the survey subjects volunteered to respond? The probability that at least one of them is careful about personal information is nothing

Step-by-step explanation:

We would assume a binomial distribution for the number of Internet users that are more careful about personal information when using a public Wi-Fi hotspot. The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - p) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 64% = 64/100 = 0.64

q = 1 - p = 1 - 0.64

q = 0.36

n = 3

1) The probability that among three randomly selected internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot is expressed as

P(x ≥ 1) = 1 - P(x < 1)

P(x < 1) = P(x = 0)

P(x = 0) = 3C0 × 0.64^0 × 0.36^(3 - 0)

P(x = 0) = 0.047

P(x ≥ 1) = 1 - 0.047 = 0.953

If more information is provided, the result would be biased.

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step-by-step explanation: