The following data represent a random sample of the ages of players in a baseball league. Assume that the population is normally distributed with a standard deviation of 1.8 years. Find the 95% confidence interval for the true mean age of players in this league. Round your answers to two decimal places and use ascending order.

Age: 32, 24, 30,34,28, 23,31,33,27,25

Step-by-step explanation:

n = 10

Mean, m = (32 + 24 + 30 + 34 + 28 + 23 + 31 + 33 + 27 + 25)/10

= 28.7

From the information given,

Standard deviation, s = 1.8

For a confidence level of 95%, the corresponding z value is 1.96.

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

It becomes

28.7 ± 1.96 × 1.8/√10

= 28.7 ± 1.12

The lower end of the confidence interval is 28.7 - 1.12 = 27.58 years

The upper end of the confidence interval is 28.7 + 1.12 = 29.82 years

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.