A researcher compares the effectiveness of two different instructional methods for teaching anatomy. A sample of 293 students using Method 1 produces a testing average of 82.9. A sample of 282 students using Method 2 produces a testing average of 76.5. Assume that the population standard deviation for Method 1 is 7.97, while the population standard deviation for Method 2 is 6.66. Determine the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 1 of 3 : Find the point estimate for the true difference between the population means.

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (5.20, 7.60).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between two population mean when the population standard deviations are known is:

The information provided is:

The critical value of z for 98% confidence interval is:

*Use a z-table for the critical value.

Compute the 98% confidence interval for the difference between two population means as follows:

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (5.20, 7.60).

b

step-by-step explanation:

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0