Java Joe Coffee Merchants makes 30 pounds of a blend that costs $4.80 per pound. This blend is made by mixing a Costa Rican coffee that costs $6 per pound with a Colombian coffee that costs $4 per pound. How many pounds of each coffee do they use in the blend?

they used 12 pounds of Costa Rican coffee and 18 pounds of Colombian coffee

Step-by-step explanation:

Let x is the number of pounds of Costa Rican coffee

Let y is the number of pounds of  Colombian coffee

Given that:

<=> x + y = 30

<=> x = 30-y (1)

<=> 6x + 4y = 144 (2)

We will substitute (1) into (2), we have:

6(30-y) + 4y = 144

<=> 180  - 6y + 4y = 144

<=> y = 2y = 36

<=> y =18 pounds

=> x = 30-18 = 12 pounds

So they used 12 pounds of Costa Rican coffee and 18 pounds of Colombian coffee

a

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2