Mathematics, 14.04.2020 12:04, soso585oo
Consider the equation x^2+(y-2)^2=1 and the relation “(x, y) R (0, 2)”, where R is read as “has distance 1 of”.
For example, “(0, 3) R (0, 2)”, that is, “(0, 3) has distance 1 of (0, 2)”. This relation can also be read as “the point (x, y) is on the circle of radius 1 with center (0, 2)”. In other words: “(x, y) satisfies this equation x^2+(y-2)^2=1 , if and only if, (x, y) R (0, 2)”.
Does this equation determine a relation between x and y? Can the variable x can be seen as a function of y, like x=g(y)? Can the variable y be expressed as a function of x, like y= h(x)? If these are possible, then what will be the domains for these two functions? What are the graphs of these two functions?
Are there points of the coordinate axes that relate to (0, 2) by means of R?
Answers: 1
Mathematics, 21.06.2019 19:30, dbenjamintheflash5
You have 17 cats that live in houses on your street, 24 dogs, 3 fish, and 4 hamsters. what percent of animals on your block are dogs?
Answers: 2
Mathematics, 21.06.2019 22:00, mileto1798
Write a description of each inequality. 1. -5a + 3 > 1 2. 27 - 2b < -6 (this < has a _ under it) 3. 1/2 (c + 1) > 5 (this > has a _ under it)
Answers: 3
Consider the equation x^2+(y-2)^2=1 and the relation “(x, y) R (0, 2)”, where R is read as “has dist...
History, 26.01.2020 06:31
Chemistry, 26.01.2020 06:31
English, 26.01.2020 06:31
Biology, 26.01.2020 06:31