There are 3 paper clips and 5 erasers in a paper sack if 2 items are drawn at random without replacement what is the probability that onwme will draw a paper clip and then an eraser

Step-by-step explanation:

This is a probability event that expresses the likelihood of an event to occur.

   Number of paper clips in sack = 3

    Number of erasers in sack  = 5

Problem: Probability that one will draw a paper clip and then an eraser?

 These are two mutually exclusive events.

   Total number of paper in sack  = 3 + 5  = 8

Pr(drawing paper clip) =

   without replacement suggests that the total number of paper in sack will reduce by 1 to 7;

 Pr(drawing eraser)  =

So:

   Pr(paper clip and eraser ) =    =

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

34

step-by-step explanation: