The radius of Circle A is three feet less than twice the diameter of Circle B. If the sum of the
diameters of both circles is 49 feet, find the area and circumference of Circle A.

Area of circle A = 1133.54 square feet

Circumference of circle A = 119.32 feet

Step-by-step explanation:

d = diameter of circle A

D = diameter of circle B

For circle A

r = 2D - 3

Therefore, the diameter of circle A is 2* the r

d = 2 * ( 2D - 3)

d = 4D - 6

and

d + D = 49

slot in the value of d

4D - 6 + D = 49

4D + D = 49 + 6

5D = 55

Divide both sides by 5

D = 11

Slot in the value of D in  d = 4D - 6

d = 4*11 - 6

d = 44 - 6

d = 38

Area of circle A = πd^2 / 4

= 3.14 * 38^2 / 4

1133.54 square feet

Circumference of circle A = πd

= 3.14* 38

= 119.32 feet

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c