Steve and Carol live 405 miles apart. They start at the same time and travel toward each other. Steve's speed is 6mph greater than Carol's. If they meet in 2.5 hours, find their speeds.

Step-by-step explanation:

GIVEN: Steve and Carol live miles apart. They start at the same time and travel toward each other. Steve's speed is greater than Carol's. If they meet in , find their speeds.

TO FIND: find their speeds.

SOLUTION:

Distance between Steve and Carol

Let the speed of Carol be

As Steve's speed is greater than Carol's.

Speed of Steve

As both are approaching towards each other

relative speed of Steve and Carol

Total time taken by both to meet each other

Total time taken by both to meet each other

speed of Carol

Speed of Steve

Hence the speed of Carol and Steve are and respectively

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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