How many real solutions does this system of equations have? X^2+ 3 = y
3x-y+1 = 0
Answer choices:
A.2
B.1
C.0
D.3

A

Step-by-step explanation:

x^2+3=y

3x-y+1=0

3x+1=y

so x²+3=3x+1

x²-3x+2=0

x²-x-2x+2=0

x(x-1)-2(x-1)=0

(x-1)(x-2)=0

x=1,2

two solutions

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!