Use slope formula, m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction, to find the slope of a line that passes through the points (–3, 8) and (4, –6).

m =
Use slope-intercept form, y = mx + b, to find the y-intercept (b) of the line.

b =
What is the new equation written in slope-intercept form, y = mx + b?

m = -2

b = 2

y= -2x+2

Step-by-step explanation:

First, slope is change in y over change in x, or rise over run. Plugging these points in, (y2-y1)/(x2-x1)=(-6-8)/(4--3), or -14/7, simplifying, the slope= -2.

Now, we have y=2x+b. Using the point (-3,8), 8=-2*-3+b, or 8=6+b, subtracting 6, 2=b.

Using slope intercept form, y=mx+b, or y=-2x+2.

The slope, intercept and linear equation of the relation given are :

Given the points :

The slope formula :

Using the linear relation :

Therefore, the slope, = - 2 and intercept = 2

The new equation written in the form y = mx + b will be ;

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f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation: