A geometry class has a total of 27 students. The number of females is 13 less than the number of males. How many males and how many females are in the class?

20 males and 7 females

Step-by-step explanation:

Let's say the number of females is x and the number of males is y.

We know that the total number of students is 27, which can also be written as x + y. So, these two expressions are equal: x + y = 27.

There are 13 fewer females than males, so: x = y - 13.

Now, we can use substitution to solve this system of linear equations.

Since x = y - 13, we can plug in y - 13 for x in x + y = 27:

x + y = 27 ⇒ (y - 13) + y = 27 ⇒ 2y - 13 = 27 ⇒ 2y = 40 ⇒ y = 20

Then, we use this value of y to solve for x:

x = y - 13 = 20 - 13 = 7

Thus, there are 20 males and 7 females.

Hope this helps!

20 males and 7 females

Step-by-step explanation:

I know this because 27= 20+7

and 20-7=13

and the question says there are 13 less then the number of males and 20-7=13 females.

I hope this helps, sorry it took me so long to answer.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.