How many 2/5s are in 1 1/2

The factorization of 8x3 -125 is (2x-5)(jx2 +kx+25)

The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. if a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. what is the margin of error of the sample mean? a. 0.086% b. 0.533% c. 1.11% d. 2.22%

[15 points, algebra 2]simplify the complex fraction and find the restrictions.