What are the zeros of the quadraic function?
f(x)=2x^2 + 10x – 12

The zeros are 1 and -6

Step-by-step explanation:

f(x)=2x^2 + 10x – 12

Set the equation equal to zero

0 =2x^2 + 10x – 12

Divide each side by 2

0/2=2/2x^2 + 10/2x – 12/2

0 = x^2 +5x -6

Factor

What 2 numbers multiply to -6 and add to 5

6*-1 = -6

6-1 =5

(x+6) (x-1) =0

Using the zero product property

x+6 =0   x-1=0

x=-6  x=1

its a little blurry tbh

step-by-step explanation:

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value