The equation of lineris y=-3x - 4. If line s runs perpendicular to line r and passes
through (4, -3), what would be the equation of lines?
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Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be perpendicular, their slopes have to be negative reciprocals of each other. (flip the sign +/- and the fraction(switch the numerator and the denominator))

For example:

Slope = 2 or

Perpendicular line's slope:  (flip the sign from + to - , and flip the fraction)

Slope =

Perpendicular line's slope:   (flip the sign from - to +, and flip the fraction)

y = -3x - 4      The slope is -3, so the perpendicular line's slope is  

Now that you know the slope, substitute/plug it into the equation,

y = mx + b

   To find b, plug in the point (4, -3) into the equation, then isolate/get the variable "b" by itself

   Subtract 4/3 on both sides to get "b" by itself

  To combine fractions, they must have the same denominator.

   Now combine the fractions

29.5977692753

step-by-step explanation:

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3