Ahyena can run one over four of a mile in 22.5 seconds. at this rate, which equation can be used to determine how fast a hyena runs in miles per hour?

Step-by-step explanation:

We know that the hyena runs a distance of

In a period of time of

However, the problem is asking for a speed in hours. We have to transform from 22.5 seconds to hours

Now, the relation of the movement is

; Where is the distance covered, the times the hyena took to covered that distance and the speed.

This is the equation we can used to find how fast the hyena runs.

Now, using given values and solving for

Therefore, the hyena runs 40 miles per hour.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

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step-by-step explanation: