Solve the problems from 4-6

4. B

5. B

6. D

Step-by-step explanation:

4. The radius is 3 units (3 boxes). So you do pi*r^2 = 3.14*9

5. You want the area of the box minus the area of the two circles.

Height of the box is 8 (bottom of circle to the top is two times the radius). Width of the box is 16 (left end of the left circle to the right end of the right circle) so 4 times the radius of the circles. Area of box is 128

Area of each circle is 3.14*(16). So you do 128 - 2*3.14*16.

6. Just plug in the radius 9 to the area of a circle formula: pi*radius^2 = 81*pi

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x