Write the slope intercept equation of a line which is parallel to y=3x+5 passing through (-6,3). Can anyone please explain with the formula?

Remember that the slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

If lines are parallel then they have the same slope (m)

This means that the slope of the line will be 3 :

y = 3x + b

Now we must find b

To do that you must plug in the point the line goes through in the x and y of the equation.

(-6, 3)

3 = 3(-6) + b

3 = -18 + b

21 = b

y = 3x + 21

Hope this helped!

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y = 3x + 21

Step-by-step explanation:

The formula of a line goes in y= mx + c

Parallel lines have different y-intercepts but the same gradients so we can assume that

y = 3x + c

Substitute in the coordinates (-6 , 3) to work out the full equation

3 = -18 + c

So c = 21

Therefore the equation of the line that is parallel to y=3x+5 passing through (-6,3) is y = 3x + 21

its totaly b

your welcome btw

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5