Find the value of R that will make the equation sin 62° = cos R true when 0° < R < 90°.

The value of R is 28° (Degrees), if the equation sin 62° = cos R true when 0° < R < 60°.

Step-by-step explanation:

The given is,

                     sin 62° = cos R

                     0° < R < 90°

Step:1

            Form the given equation,

                        sin 62° = cos R.......................(1)

           Where,

                     sin 62° = 0.88295

           From the value of sin 62, equation (1) becomes

                      sin 62° = cos R

                       0.88295 = cos R

                            R = 0.88295

                                  R = 27.9997

                                     ≅ 28°

                                  R = 28°

Step:2

              Check for solution,

               From equation 1,

                             sin 62° = cos R

              Substitute R = 28°,

                             sin 62° = cos 28°

                          0.88295 = 0.88295

Result:

         The value of R is 28° (Degrees), if the equation sin 62° = cos R true when 0° < R < 60°.

i do not know the answer

step-by-step explanation:

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2