Let f(x) = 4(x^2) - 3x
g(x) = (x^2) - x + 3.
Find (f + g)(x), (f - g)(x), (fg)(x), and (Start Fraction f/g , End Fraction )(x). Give the domain of each.

(f+g)(x)=5x²-4x+3

(f-g)(x)=3x²-2x+3

(fg)(x)

Step-by-step explanation:

Given that,

f(x)=4x²-3x

g(x)=x²-x+3

(f+g)(x)

=f(x)+g(x)

=4x²-3x+x²-x+3

=(4x²+x²)+(-3x-x)+3   [ combined the like terms]

=5x²-4x+3

(f-g)(x)

=f(x)-g(x)

=4x²-3x-(x²-x+3)

=4x²-3x-x²+x-3

=(4x²-x²)+(-3x+x)-3   [ combined the like terms]

=3x²-2x+3

(fg)(x)

=f(x).g(x)

=(4x²-3x).(x²-x+3)

=4x²(x²-x+3)-3x(x²-x+3)

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24