Tony went on an 8-mile run. For
the first 1/3 of an hour he ran at a
constant speed. For the last 3⁄4 of an
hour he ran at a constant speed that
was 2 miles per hour faster than his
original speed. What was his original
speed, and what was his ending scene on the run?

The first rate is 6 miles per hour

The final rate is 6+2 or 8 miles per hour

Step-by-step explanation:

We know d = rt  where distance is equal to rate times time

First part

d1 = r * 1/3

Second part

d2 = (r+2)(3/4)

We know the total distance is 8 miles and is

d1+d2 = 8

r * 1/3 + (r+2)(3/4) = 8

Multiply each side by 12 to get rid of the fractions

12( r * 1/3 + (r+2)(3/4)) = 8*12

4r +(r+2) 9 = 96

Distribute

4r+ 9r +18 = 96

Combine like terms

13r +18 = 96

Subtract 18 from each side

13r+18-18 = 96-18

13r = 78

Divide each side by 13

13r/13 = 78/13

r=6

The first rate is 6 miles per hour

The final rate is 6+2 or 8 miles per hour

Original speed: 6 miles per hour

Ending: 8 miles per hour

Step-by-step explanation:

Speed = distance/time

Distance = speed × time

Let S be the original speed

(S × ⅓) + [(S + 2) × ¾] = 8

S/3 + 3S/4 + 3/2 = 8

Lcm: 12

(S×4 + 3S×3)/12 = 8 - 3/2

13S/12 = 13/2

S = 13/2 × 12/13

S = 6

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

answer: 7

step-by-step explanation: