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Step-by-step explanation:

One way to determine if the equation has any real solutions is to look at its discriminant. For the equation ax²+bx+c = 0, the discriminant is ...

  d = b² -4ac

When the discriminant is negative, both solutions to the quadratic are complex. There are no real solutions in that case.

We can find the discriminant values to be ...

  A: d = 2² -4(1)(4) = -12 . . . . no real zeros

  B: d = 0² -4(3)(-5) = 60 . . . two real zeros

  C: d = 8² -4(-2)(0) = 64 . . . two real zeros

  D: d = 10² -4(1)(26) = -4 . . .no real zeros

Expressions A and D have no real zeros.

Comment on the question

You are given an expression, not an equation. There is no equal sign. Hence, we cannot talk about solutions. We can only talk about zeros, values of x that make the expression have a value of zero.

step-by-step explanation:

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents