The circle below is centered at (4, -1) and has a radius of 3. What is its
equation?
O A. (x-4)^2 + (y - 1)^2 = 9
O B. (x-4)^2 + (y - 1)^2 = 3
O C. (x-4)^2 + (y + 1)^2 = 9
O D. (x-4)^2 + (y + 1)^2 = 3

The square root of 9x plus 7 plus the square rot of 2x equall to 7

Look at triangle wxy what is the length (in centimeters) of the side wy of the triangle?

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)