If a bug can flap its wings at a rate of 60 times in 2 seconds, how many times do they flap their wings in 2.604 minutes? Round to 1 decimal.

4,687.2 flaps

Step-by-step explanation:

#We calculate the number of flaps per second:

#Since one minute has 60 seconds, we will multiply our time by 60 seconds and then by flaps/second:

Hence, the bird makes 4,687.2 flaps in 2.604 minutes.

reduce the friction between its moving parts

step-by-step explanation:

in fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: