Point P'P
′
P, prime is the image of P(6,0)P(6,0)P, left parenthesis, 6, comma, 0, right parenthesis under the translation (x, y)\to(x-6,y-1)(x, y)→(x−6,y−1)left parenthesis, x, comma, y, right parenthesis, \to, left parenthesis, x, minus, 6, comma, y, minus, 1, right parenthesis.
What are the coordinates of P'P
′
P, prime?

The coordinate of P' will be (0, -1)

Translation is a way of shifting an object in the xy plane to another location.

Given the coordinate of P(6, 0)

x = 6

y =0

If the image P is translated under the rule (x,y)→(x−6,y−1), the resulting image will be at:

P' = (6-6, 0 - 1)

P' = (0, -1)

Hence the coordinate of P' will be (0, -1)

Learn more here: link

Given:

The point P' is the image of the point P under the translation

The coordinates of the point P are (6,0)

We need to determine the coordinates of the point P'

Coordinates of the point P':

The coordinates of the point P' can be determined by substituting the coordinates of the point P(6,0) in the translation.

Thus, substituting the coordinates, we have;

Simplifying the coordinates, we get;

Thus, the coordinates of the point P' is (0,-1)

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}