Mathematics, 19.01.2020 00:31, julianl25646

Given that the rate constant for the decomposition of hypothetical compound x from part a is 1.60 m−1⋅min−1, calculate the concentration of x after 13.0min .

(min) [x](m)
0 0.467
1 0.267
2 0.187
3 0.144
4 0.117
5 0.099
6 0.085
7 0.075

Answers: 1

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Answers

Using the 2nd order integrated rate law.

1/A1 = 1/A0 + Kt

A1 = 0.267
A0 = 0.467
k = 1.6
t = time

1/A13 = 1/0.467 + 1.6(13)
1/A13 = 1/0.467 + 20.8
1/A13 = 2.141 + 20.8
1/A13 = 22.941
1 = 22.941 * A13
1/22.941 = A13
A13 = 0.04359

The concentration of X after 13 minutes is 0.04359

answered: mel8260

The concentration of X after $13{\text{ minutes}}$ is $\boxed{0.04359}.$

Further explanation:

Given:

The rate constant for the decomposition $k = 1.6{M^{ - 1}}{m^{ - 1}}.$

Explanation:

The second order integrated rate law can be expressed as follows,

$\boxed{\frac{1}{{{N_0}}} = \frac{1}{{{N_1}}} - kt}$

Here, ${N_0}$ represents the initial concentration, ${N_1}$ represents the concentration after time t and k represents the constant.

The concentration after 13 minutes can be obtained as follows,

$\begin{aligned}\frac{1}{{{N_{13}}}} - kt &= \frac{1}{{{N_0}}}\\ \frac{1}{{{N_{13}}}} - 1.6\left( {13} \right) &= \frac{1}{{0.467}}\\\frac{1}{{{N_{13}}}} &= 2.14 + 20.8\\\frac{1}{{{N_{13}}}} &= 22.94\\{N_{13}} &= \frac{1}{{22.94}}\\\end{aligned}$

The concentration of X after $13{\text{ minutes}}$ is $\boxed{0.04359}.$

Learn more:

If the clothing maker bought 500 m2 of this fabric, how much money did he lose? use 1tepiz=0.625dollar and 0.9144m=1yard link. Suppose that you find the volume of all the oceans to be 1.4×109km3 in a reference book. to find the mass, you can use the density of water, also found in this reference book, but first you must convert the volume to cubic meters. What is this volume in cubic meters?link.

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Exponential function

Keywords: rate, constant, decomposition, integral, hypothetical, compound, X, part A, 1.60, concentration, 13 minutes.

answered: Guest

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

answered: Guest

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

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Given that the rate constant for the decomposition of hypothetical compound x from part a is 1.60 m−...