Find the area of polygon with A(-6,-3) ,B (2,-3), C (2,1) , D (-6,1)?

That's a rectangle oriented along the axes.

AB=2 - -6 = 8

BC = 1 - -3 = 4

CD = 2 - -6 = 8

AD = 1 - -3 = 4

Area is 8×4=32

32

The Shoelace Formula tells us the signed area of any polygon given the 2D vertices in order.  It's half the sum of the cross product of the sides.  If successive vertices are (a,b),(c,d) the cross product is ad-bc.

A(-6,-3) ,B (2,-3), C (2,1) , D (-6,1)

area = (1/2) ( (-6)(-3) - (-3)(2) + (2)(1) - (-3)(2) + 2(1) - 1(-6) + (-6)(-3) - (1)(-6)) = 32

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: