A rectangular box is twice as long as it is wide and twice as wide as it is high. The sum of its length,
width and height is 35 inches. What are the dimensions of the box?

ok so the

the length is 20

the width is 10

the height is 5

Step-by-step explanation:

ok i got this by guess and check

twice as long as it is wide so i am saying that it is 10 wide so it would be 20 long and if it is twice as wide as it is tall then it is 5 because 10/2=5

20+10+5=35

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)