Which statements about the graph of the function f(x) = 2x^2– x – 6 are true? Select two options.

Step-by-step explanation:

Please, share the answer options next time.

1)  f(x) = 2x^2– x – 6 is a quadratic function.  

2) The coefficients of this polynomial are a = 2, b = -1 and c = -6

2)  Its graph opens up.

3)  The x-value of the axis of symmetry and the vertex is x = -b / (2a), which here comes out to x = -(-1) / [2(2)], or x = 1/4

4) the y coordinate of the vertex is f(1/4), or -6 1/8

5) The vertex is at (1/4, -6 1/8)

6)  The y-intercept is at f(0):  2(0)^2 - 0 - 6 = -6  =>  (0, -6)

chiken

step-by-step explanation:

the opening of this porabola is facing up

step-by-step explanation: